Question

Only For Genius

Explain why the reactance offered by an indicator increases with increasing frequency of an alternating voltage.

Answer 1

an indicator opposes the flow of current and develops a back emf on itself
according to lenz's law the induced current opposes both the growth and decay of current
since the induced emf is proportional to the rate of change of current ,the rate of change of current is faster

it this correct I doubt myself

Answer 2

hey mate ,

here is your answer,

→An inductor opposes the flow of current , because it develops a back emf in itself .

→According to lenz's law , the induced current opposes both the growth and decay of current .

→Since induced emf is proportional to the rate of change of current , it will provide greater reactance to the flow of current , if the rate of change of current is faster .

→Hence the reactance of inductor is directly proportion the frequency of a.c supplied .

i.e., XL=2πγL

hope this helps you.

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