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dhruvparikh:
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Heya mate, Here is ur answer
Let us take theta as A
Given Cot A =7/8
1)
![\frac{(1 + sin \: a)(1 - sin \: a)}{(1 + cos \: a)(1 - cos \: a)} \frac{(1 + sin \: a)(1 - sin \: a)}{(1 + cos \: a)(1 - cos \: a)}](https://tex.z-dn.net/?f=%5Cfrac%7B%281+%2B+sin+%5C%3A+a%29%281+-+sin+%5C%3A+a%29%7D%7B%281+%2B+cos+%5C%3A+a%29%281+-+cos+%5C%3A+a%29%7D+)
We know that (a+b)(a-b)=a^2 -b^2
=![\frac{1 {}^{2} - {sin \: }^{2}a }{1 {}^{2} - cos \: {}^{2}a } \frac{1 {}^{2} - {sin \: }^{2}a }{1 {}^{2} - cos \: {}^{2}a }](https://tex.z-dn.net/?f=%5Cfrac%7B1+%7B%7D%5E%7B2%7D+-+%7Bsin+%5C%3A+%7D%5E%7B2%7Da+%7D%7B1+%7B%7D%5E%7B2%7D+-+cos+%5C%3A+%7B%7D%5E%7B2%7Da+%7D)
We know that 1 - sin ^2 A = cos ^A
And 1 - cos^2 A = Sin ^2 A
=![\frac{cos \: {}^{2}a }{sin \: {}^{2} a} \frac{cos \: {}^{2}a }{sin \: {}^{2} a}](https://tex.z-dn.net/?f=%5Cfrac%7Bcos+%5C%3A+%7B%7D%5E%7B2%7Da+%7D%7Bsin+%5C%3A+%7B%7D%5E%7B2%7D+a%7D)
We know that Cos A/ Sin A = Cot A
So,
=![cot { {}^{} }^{2} a cot { {}^{} }^{2} a](https://tex.z-dn.net/?f=cot+%7B+%7B%7D%5E%7B%7D+%7D%5E%7B2%7D+a)
=![( \frac{7}{8}) {}^{2} ( \frac{7}{8}) {}^{2}](https://tex.z-dn.net/?f=%28+%5Cfrac%7B7%7D%7B8%7D%29+%7B%7D%5E%7B2%7D)
=![\frac{49}{64} \frac{49}{64}](https://tex.z-dn.net/?f=+%5Cfrac%7B49%7D%7B64%7D)
Also, Cot ^2 A =49/64
========================
Warm regards
@Laughterqueen
Be Brainly ✌✌
Let us take theta as A
Given Cot A =7/8
1)
We know that (a+b)(a-b)=a^2 -b^2
=
We know that 1 - sin ^2 A = cos ^A
And 1 - cos^2 A = Sin ^2 A
=
We know that Cos A/ Sin A = Cot A
So,
=
=
=
Also, Cot ^2 A =49/64
========================
Warm regards
@Laughterqueen
Be Brainly ✌✌
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