Question

➡ only for part ( i )
please give a correct answer ★

❤ thank you❤​

Answer 1

$\underline\bold\red{♡Hy \:Mate♡}$

Your Answer Is Giving Attachment :)

» нορє iτ нєℓρѕ γου «

❤✨τнαиκ γου✨❤

Answer 2

Step-by-step explanation:

$\tt {(cosec\theta - cot\theta)}^{2} = \frac{1-cos\theta}{1+cos\theta} \\ \\ \tt L.H.S. = {(cosec\theta - cot\theta)}^{2} \\ \\ \tt \longrightarrow L.H.S = {( \frac{1}{sin\theta} - \frac{cos\theta}{sin\theta})}^{2} \\ \\ \tt \longrightarrow L.H.S = {(\frac{1-cos\theta}{sin\theta})}^{2} \\ \\ \tt \longrightarrow L.H.S. = \frac{{(1-cos\theta)}^{2}}{{sin}^{2}\theta} \\ \\ \tt \longrightarrow L.H.S = \frac{{(1-cos\theta)}^{2}}{1-{cos}^{2}\theta} \\ \\ \tt \longrightarrow L.H.S. = \frac{{(1-cos\theta)}^{2}}{(1-cos\theta)(1+cos\theta)} \\ \\ \tt \longrightarrow L.H.S. = \frac{1-cos\theta}{1+cos\theta} \\ \\ \tt \longrightarrow L.H.S = R.H.S$