Question

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Question: A man buys a horse for $60. He sells the horse for $70. He then buys the horse back for $80. And he sells the horse again for $90. In the end, how much money did the man make or lose? Or did he break even?


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Answer 1

Answer:

The man first bought a horse for $ 60 .

Then the man sold the horse for $ 70 .

Hence the Cost price of the horse was $ 60 .

Selling price of the horse of the horse was $ 70 .

Since the S.P > C.P we have a profit here .

Profit = S.P - C.P

⇒ Profit = $ 70 - $ 60

⇒ Profit = $ 10

The first profit is $ 10 .

Then he buys the horse for $ 80 .

Then the horse is again sold for $ 90 .

Hence the Cost price of the horse was $ 80 .

Selling price of the horse of the horse was $ 90 .

Since the S.P is again more than the C.P we again have a Profit here .

Profit = S.P - C.P

⇒ Profit = $ 90 - $ 80

⇒ Profit = $ 10

The second profit is $ 10 .

The total profit is $ 10 + $ 10

⇒ $ 20

The man made $ 20 profit in the whole transaction .

Answer 2

ANSWER

$20

Step By Step Explanation

This question can be solved in two parts.

~The first part

Cost Price(C.P) of the horse = $60

Selling Price(S.P) of the horse = $70

So,we know that

Profit > is the extra money a person gains when the Cost price of any object is less than Selling price.

i.e. Profit = S.P - C.P

=> Profit = $( 70 - 60 )

=> Profit = $10

Hence the profit made by the person in the first case is $10.

~The second Case

Cost Price(C.P) of the horse = $80

Selling Price(S.P) of the horse = $90

Now, Profit = S.P - C.P

=>Profit = $90 - $80

=>Profit = $10.

So the profit in second case is $10.

Hence from both the cases and the transactions made by the man for horse , the profit made is =>

$10 + $10

=> $20