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Question number-8

Answer 1

Answer:

109200

Step-by-step explanation:

First we have to find the L.C.M of 8,15 and 21

that is = 840

Now dividing 110000 by 840

remainder will be 800

So nearest no to be divisible by 8,15,21 is = 110000 - 800

                                                                     = 109200

Answer 2

Answer: 1,10,040

Step-by-step explanation:

First let me find the LCM of the given numbers, 8, 15 and 21.

We get LCM = 840

The number is nearest to 1,10,000.

So divide 1,10,000 by 840. We get quotient 130 and remainder 800.

So multiply 840 by 130 and 131 each, and then find the one among them which is closer to 1,10,000 than the other.

130 × 840 = 1,09,200

131 × 840 = 1,10,040.

Difference between 1,09,200 and 1,10,000 is 800.

Difference between 1,10,040 and 1,10,000 is 40.

So 1,10,040 is the closest.

∴ 1,10,040 is the answer,

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