Question

*Only Maths.*
*No trick.*

A man has 25 cows.
They are numbered from 1 to 25.
Each cow gives milk equal to the number allotted to it i.e. cow numbered 1 gives 1 liter milk, cow numbered 2 gives 2 liters milk........ cow numbered 25 gives 25 liters milk.
The man has 5 sons.
The man wants to give 5 cows to each son and also wants that each son should get equal quantity of milk.
So make suitable groups of cows with their numbers.​

Answer 1

Answer:

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Answer 2

Solution:

Given,

a=1

l=25

n=25

To Find,

Sn

Sn=n/2(a+l)

=25/2(25+1)

=25×13

=325

25 cows totally produce 325 litres.

The man has 5 sons.

Then each sons get 1/5th of 325 litres.

Then each of them gets 65 litres.

Now we know a=1,d=1,Sn=65

Sn=n/2[2a+(n+1)d]

65=n/2[2+(n+1)]

130=2n+n(n+1)

130=2n+n^2+n

130=3n+n^2

n^2+3n-130=0

n=10

Similarly,

1-10cows for 1st son.

11-15cows for 2nd son.

16-19cows for 3rd son.

20-22cows for 4th son.

23-25cows for 5th son.