Question

only moderator can solve

Answer 1

Here,

AD=BC (given)

ang.ACD=ang.BDC (bisecting 90°)

CD=CD (common)

Thus ∆ADC=∆BDC

Answer 2

ⓗⓔⓨ ⓕⓡⓘⓔⓝⓓ


ⓗⓔⓡⓔ ⓘⓢ ⓨⓞⓤⓡ


ⓐⓝⓢⓦⓔⓡ




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⊙ In triangle ADC and BCD


AC= BD ( Given )


Angle ACD = Angle BDC ( Given )


CD = DC ( Common side )


so, triangle ADC is congruent to Triangle BCD



$hope \: it \: helps$





$<marquee > prabhudutt$