Question

only moderator challenge

Answer 1

here is ur ans broo hope it will help u

Answer 2

$\text{Answer :}$

Angles of triangle are in ratio - 2 : 4 : 6

Let the common ratio - x

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We know that -

Sum of all angles of a ∆ = 180°

In ∆ ABC

A + B + C = 180°

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Sided of ∆ are -

$\textbf{A \: = \: 2x \\ \\ B \: = \: 4x \\ \\ C \: = \: 6x}$

Hence,

$= > 2x + 4x + 6x = 180 \\ \\ = > 12x = 180 \\ \\ = > x = \frac{180}{12} \\ \\ = > x = 15$

$\textbf{If x = 15}$

$\underline\textbf{A = 2x = 2 \times 15 = 30 }$

$\underline\textbf{B = 4x = 4 \times 15 = 60 }$

$\underline\textbf{ C= 6x = 6 \times 15 = 90 }$

To check :

A + B + C = 180°

Put the values :

A = 30°

B = 60°

C = 90°

A + B + C = 180°

30° + 60° + 90° = 180°

90° + 90° = 180°

180° = 180°

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$\text{Tysm for the question!}$