Question

Only the part (a)
Don't answer if u don't know the answer or else I will report it.
so please don't answer for points​

Answer 1

Answer:

Step-by-step explanation:

Consider ΔABC, with right angle at B,

By Pythagoras Theorem,

(Hypotenuse)² = (Base)² + (Height)²

=> AC² = AB² + BC²

=> AC² = (18)² + (7.5)² = 324 + 56.25 = 380.25

=> AC = √380.25 = 19.5 cm.

Further we know that Sinθ = Opposite side to θ/ Hypotenuse

Siny° = Opposite side to y°/Hypotenuse

        = 7.5/19.5 = 75/195 = 5/13 ----- (1)

Now Consider the ΔARS, with Right angle at R,

Siny° = Opposite side to y°/Hypotenuse = SR/AS = 5/AS

//from (1), we know that Siny = 5/13.

=>  5/13 = 5/AS

=> AS = 13 cm.

Now by Pythagoras Theorem,

(Hypotenuse)² = (Base)² + (Height)²

 AS² = AR² + RS²

=> AR² = AS² - RS² =    13² - 5² = 169 - 25 = 144

=> AR = √144 = 12 cm.

But AB = AR + RB

=>       18   = 12 + RB

=> RB = 6 cm.

Now Consider Δ BRS with right angle at R.

we know that Tanθ = Opposite side to θ/ Adjacent side to θ

 Tanx° = Opposite side to x°/Adjacent Side to x° = RB/RS = 6/5.