Onsider the experiment of tossing a coin. If the coin shows tail toss it again but if it shows head then throw a die. Find the conditional probability of the event the die shows a number greater than 3 given that there is at least one head.
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Event h, h its, its probability equal 1 by 2 into 1 by 2 equal 1 by 4.
when they even will be its tea then the probability is 1 by 2 into 1 by 2 equal 1 by 4. if the event is tand 1 then the probability will be 1 by 2 into 1 by 3 equal 1 by 12.
when they even if 3 and 1 then the probability will be 1 by 2 into 1 by 6 = 1 by 12.
find T3 T4 t5 and t6.
we need to find p (E/F) Fmeans number of greater than 4 on the die.
E means at least one head.
P =1/12+1/12
=1/6.
then find F,
Then add all,
P(F)=3/4
by formula,
=1/6/3/4
=2/9.
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