Question

/OPA=/OPB SEG OP ! CHORD
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Answer 1

Answer:

OP A=/SEG/HTML ¥T OP !!@CHORD

Answer 2

In △s OPA and OPB,

OP = OP (Common)

OA = OB (Radius of the circle)

AP = BP (P is the mid point of AB)

Hence, △OPA≅△OPB (SSS rule)

Thus, ∠OPA=∠OPB=x (By cpct)

∠OPA+∠OPB=180 (Angles on a straight line)

x+x=180

x=90

∠OPA=∠OPB=90∘

or, OP is perpendicular to AB