Math, asked by Anonymous, 1 year ago

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If 9999 = 4, 8888 = 8, 1816 = 6, 1212 = 0, then 1919 =?

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Answers

Answered by Kusumsahu7
18
<b>

Hi bro here is your answer

So, your question is If 9999 = 4, 8888 = 8, 1816 = 6, 1212 = 0, then 1919 =?

So answer is here

1+1+1+1=4, 9+1=10, 9+1=10,9+1=10

2+2+2+2=8, 8+2=10, 8+2=10, 8+2=10

2+4=6, 18+2=20, 16+4=20

1+1=2

So, 19+1=20, 19+1=20

So answer is 2 ..

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Hope its help you

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Anonymous: sisso❤
Anonymous: Fabulous Answers
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Anonymous: Nice answer :)
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Answered by Sauron
25

Answer :



1919 = 2



Explaination :-

• The logic is that the answer of each number is the number of areas enclosed or holes present in the number.

• In 9999 , the closed areas = 4 which gets multiplied by 1 because the same number has 4 holes.


=> 4 × 1

\large{\green{\boxed{\green{\boxed{\red{\textsf{ 9999 = 4 }}}}}}}


• In 8888 , the closed areas = 8 gets multiplied by 1 because the same number( 8 ) has 8 holes.

=> 8 × 1

\large{\green{\boxed{\green{\boxed{\red{\textsf{8888 = 8 }}}}}}}


• 1212 , the closed areas are 0

=> 0 × 0

\large{\green{\boxed{\green{\boxed{\red{\textsf{1212 = 0 }}}}}}}


• Then , 1919 =

=> closed areas = 2

=> It gets multipled by 1 because only one number ( 9 ) had closed areas.

=> 2 × 1

=> 2

\large{\pink{\boxed{\blue{\boxed{\red{\textsf{1919 = 2 }}}}}}}

\therefore 1919 = 2


Kusumsahu7: nyc siiso
Sauron: ☺️❤️❤️Thankies Behna ❤️❤️☺️
Anonymous: Nice answer :)
Sauron: ❤️✌️ Thank u ✌️❤️
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