x=7-4√3;then √x+1/√x=?
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x = 7 - 4√3
1/x = 1/(7 - 4√3) * (7 + 4√3)/(7 + 4√3)
1/x = (7 + 4√3)/(49 - 48)
1/x = (7 + 4√3)
now,
(√x + 1/√x)² = x + 1/x + 2*√x *1/√x
(√x + 1/√x)² = (7 - 4√3) + (7 - 4√3) + 2
(√x + 1/√x)² = 14 + 2
(√x + 1/√x)² = 16
(√x + 1/√x) = 4.
1/x = 1/(7 - 4√3) * (7 + 4√3)/(7 + 4√3)
1/x = (7 + 4√3)/(49 - 48)
1/x = (7 + 4√3)
now,
(√x + 1/√x)² = x + 1/x + 2*√x *1/√x
(√x + 1/√x)² = (7 - 4√3) + (7 - 4√3) + 2
(√x + 1/√x)² = 14 + 2
(√x + 1/√x)² = 16
(√x + 1/√x) = 4.
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