Question

open challenge to whom people who love maths

solve this question refer to picture in your notebook and give me answer fast ohhk or give step by step explanation


if you don't know then don't answer

asking time and date 3 March 2018 5.46 4 sec according to Indian clock

give me answer in just minutes

your time start now

Answer 1

★★★hiiiii friend!!★★★
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Solution:We can note that the class intervals are not continuous. So, we will make them continuous.

 Lower limit of any random class - Upper limit of previous class = 7-6 = 1 and half of 1 is equal to 0.5.So, we will subtract 0.5 from all the lower limits and will add 0.5 to all the upper limits. Doing so, we will have continuous class intervals:

We can find class marks for both of the teams. Class intervals are same for both the teams which means that class marks will also be same for both the teams.

Class mark =(lower limit + upper limit)/2

below the answer there is a pic u can check the table from there....!!

Now, we can draw frequency polygons for both the teams.

below there is also drawn a frequency polygons u can see!!

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★★★i hope this may help u!!★★★