OPQR is square ('O' being origin) and men are middle points of sides PQ,gr respectively and the
ratio of areas of square and triangle omnis - ( where P,q are relatively prime) then P-q is??
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Answer:
Area of square =a2
Area of ΔOMN=21{0(2a−a)+a(a−0)+2a(0−2a)}
=21{a2−4a2}
=21×44a2−a2=83a2
Area of ΔOMNArea of square=83a2a2=38
Given that the ratio of square OPQR and △OMNis 6λ,
Now
6λ=38
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