option.
What is the value of log 375 + 2log 15 -3 log 137
Given that, log 2 = 0.3012, log 3
= 0.4771 and log 5=0.6989
Answers
Step-by-step explanation:
this is the answer for your question
The value of log 375 + 2log15 - 3log137 is -1.4843.
Given,
log 2 = 0.3012, log 3 = 0.4771, and log 5 = 0.6989
To find,
The value of log 375 + 2 log 15 - 3 log 137
Solution,
We can simply solve this numerical by following this process.
375 can be written as 125 x 3.
We get log 375 = log (125 x 3).
By the property of logarithm, log (a x b) = log a + log b. Hence, we get log 375 = log 125 + log 3.
Also, 125 can be written as 5^3. So, we get log 125 = log (5^3). By the property of logarithm, log(a^b) = b x log(a). Hence, we get log 125 = 3 log5
Here, we get log 375 = 3 log 5 + log 3. (equation 1)
2log15 = 2 log(5 x 3). Or, 2 log 15 = 2(log 5 + log 3).
Or, 2 log 15 = 2 log 5 + 2 log 3. (equation 2)
3 log 137 = 3 x 2.1367 (We find value of log 137 from log table). (Equation 3)
So, the final result will be equation1 + equation 2 - equation 3.
Or, (3 x 0.6989 + 0.4771) + (2 x 0.6989 + 2 x 0.4771) - (3 x 2.1367)
(Put values of log 2, log 3, and log 5 above)
So, we get 2.5738 + 2.352 - 6.4101 = -1.4843.
This is the final answer. The value of log 375 + 2log15 - 3 log 137 = -1.4843.
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