Question

or
Electric potential at a distance 0.9 m from a charge is +50 V. Find the
magnitude and nature of charge.​

Answer 1

Answer:

Explanation:

Assume, a point P from point charge q

V=+50V

distance between the charge and a point = 0.9m

V = 1/ 4πεо * q/r

50= 9*10^9*q/0.9

q= 50*0.9/9*10^9

q= +5*10^-9C

thus the point charge is positive in nature

hope it helps u