order of dipole moment of CH3Cl,CH2Cl2,CHCl3, CCl4 and reason
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In case of CCl4, tetrahedral symmetry exists. Therefore, the dipole moment of three C-Cl bonds on one side, gives a resultant moment that is equal and opposite to the dipole moment of the single C-Cl bond on the opposite side. So, μ=0. This explains CHCl3>CCl4.
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