Order of filling of electrons in the orbitles of an atom will be
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Then Denominator=2x+1
Fraction =2x+1x
Reciprocal of the fraction =x2x+1
It is given that the sum fo the fraction and its reciprocal is 22116
∴2x+1x+x2x+1=22116
⇒x(2x+1)x2+(2x+1)2=2158⇒2x2+x5x2+4x+1=2158
⇒21(5x2+4x+1)=58(2x2+x)⇒105x2+84x+21=116x
⇒11x2−26x−21=0⇒11x2−33x+7x−21=0⇒11x(x−3)+7(x−3)=0
⇒(11x+7)(x−3)=0⇒x=3,−117
∵ x can not be a negative
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