order of reactivity of primary, secondary and tertiary alcohol with Na metal?
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The order of reactivity of alcohols with sodium metal is,
primary>secondary>tertiary
Here sodium metal displaces hydrogen from the -OH group thus giving us a carbanion intermediate -O⁻Na⁺
CH3
Example: I
CH3-CH2-CH2-CH2-OH > CH3-CH2-CH-OH > CH3-C-OH
I I
CH3 CH3
primary>secondary>tertiary
Here sodium metal displaces hydrogen from the -OH group thus giving us a carbanion intermediate -O⁻Na⁺
CH3
Example: I
CH3-CH2-CH2-CH2-OH > CH3-CH2-CH-OH > CH3-C-OH
I I
CH3 CH3
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