Chemistry, asked by Physicist28, 1 year ago

order of reactivity of primary, secondary and tertiary alcohol with Na metal?

Answers

Answered by siril
2
The order of reactivity of alcohols with sodium metal is,

primary>secondary>tertiary

Here sodium metal displaces hydrogen from the -OH group thus giving us a carbanion intermediate -O⁻Na⁺
                                                                                   CH3
Example:                                                                      I
CH3-CH2-CH2-CH2-OH > CH3-CH2-CH-OH > CH3-C-OH
                                                            I                        I
                                                          CH3                  CH3         

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