Question

Ordinary light incident on a glass slab, at the polarizing angle, suffers a deviation of 22°.The value of angle of refraction is..........,choose the correct option from the given options.
(A) large value of magnification
(A) 74°
(B) 22°
(C) 90°
(D) 34°

Answer 1

The right answer is option no.A

Answer 2

Answer:

d) 34°

Explanation:

Let the angle of incidence = i

Let the angle of reflection = r

Let the angle of refraction = r'

Angle of refraction = ∠r' = i - 22

Angle of reflection = i = r + 22

As the light is incident on the glass slab thus we will have a polarizing angle

Polarizing angle = 0 = θp = 90−r  

Angle of deviation, δ = θp − r = 22  

⇒ (90−r)−r =22  

2r = 90−22

2r = 68  

r = 34

Thus, the value of angle of refraction is 34°