Question

Organic compound ‘A’ of molecular formula C₂H₆O liberates hydrogen gas with sodium
metal. ‘A’ gives ‘B’ of formula C₄H₁₀O, when it reacts with concentrated H₂SO₄ at
413K. At 443K with concentrated H₂SO₄ ‘A’ gives compound ‘C’ of formula C₂H₄. This
compound ‘C’ decolourises bromine water. What are ‘A’, ‘B’ and ‘C’?

Answer 1

Dear Student,

◆ Answer -

• Compound A => Ethanol
• Compound B => Diethyl ether
• Compound C => Ethene

◆ Reactions -

Ethanol (A) liberates hydrogen gas with sodium

metal.

2C2H5-OH + 2Na --> 2C2H5-ONa + H2

Ethanol (A) reacts with concentrated H₂SO₄ at 413K to give dimethyl ether (B).

2C2H5-OH --> C2H5-O-C2H5 + H2O

Ethanol (A) reacts with concentrated H₂SO₄ at 443K to give ethene (C).

C2H5-OH --> CH2=CH2 + H2O

Ethene (C) reacts with bromine water to form ethyl dibromide which is colourless.

CH2=CH2 + Br2 --> Br-CH2-CH2-Br

Thanks dear...