What is the product formed when Ethanol is heated with excess concentrated H₂SO₄ at 443K, and What happens when this gas is passed through
bromine water?
Answers
Answered by
0
Answer:
firstly H2SO4 is break down at 443k and after that it teact with the ethanol
Answered by
0
When ethanol is heated at 170°C or 443 K with excess concentrated sulphuric acid, ethene the unsaturated hydrocarbon is dehydrated. The reaction that occurs is -
CH3-CH2OH (ethanol) = CH2 + H20 (water)
In the reaction -
- The concentrated sulphuric acid functions as a dehydrating agent in this response that removes molecules of water from the ethanol molecule.
- If hydrogen is added to ethene the product of the above equation in the presence of catalysts such as palladium or nickel, then one atom of H contributes a single bond in ethane to each carbon atom of ethene.
Similar questions
Geography,
5 months ago
Computer Science,
5 months ago
Physics,
10 months ago
Physics,
10 months ago
Science,
1 year ago