Question

What is the product formed when Ethanol is heated with excess concentrated H₂SO₄ at 443K, and What happens when this gas is passed through
bromine water?

Answer 1

Answer:

firstly H2SO4 is break down at 443k and after that it teact with the ethanol

Answer 2

When ethanol is heated at 170°C or 443 K with excess concentrated sulphuric acid, ethene the unsaturated hydrocarbon is dehydrated. The reaction that occurs is -

CH3-CH2OH (ethanol) = CH2 + H20 (water)

In the reaction -

- The concentrated sulphuric acid functions as a dehydrating agent in this response that removes molecules of water from the ethanol molecule.

- If hydrogen is added to ethene the product of the above equation in the presence of catalysts such as palladium or nickel, then one atom of H contributes a single bond in ethane to each carbon atom of ethene.