Origin is the centre of circle passing through the vertices of an equilateral triangle whose median is of length 3a then equation of the circle is
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Equation of a circle passing through the origin is x2+y2=a2
If the centroid of the triangle with the centre of the circle, then the radius of the circle is 32 of the length of the medion.
∴r=32×3a
⟶r2=4a2
∴x2+y2=4a2
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Answer:
Correct option isDx 2 +y 2 +4a 2
Equation of a circle passing through the origin is
x 2 +y 2 =a 2
If the centroid of the triangle with the centre of the circle, then the radius of the circle is 32
of the length of the medion.
∴r= 32 ×3a⟶r 2 =4a 2
∴x 2 +y 2 =4a 2
Step-by-step explanation:
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