Orthocentre of a Triangle with vertices (0,0) (3,4) and (4,0) is ?
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Heya,
Please see the attachment for your solution..
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Please see the attachment for your solution..
HOPE IT HELPS:-))
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Anonymous:
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triangle ABC ', vertices are A(,4) , B (0,0) ,C (4,0)
O is the orthocentre triangle
By considering the coordinates of B ,C,A we can cinclude that :
Equation of BC is y=0 .......(1)
equation of AD is x=3 ......(2)
As we know slope of BBC (begin in on the x axis)=0
and for a vertical line AD however the slope is not defined. it does not have a slope
we take the slope of AC = (4-0)/(3-4)=4/-1=-4
So the slope of its perpendicular BE has to be its negative reciprocal . that is the slope of the= 1/4
So equation of bird which is passing through (0,0) has to be y= mx + b , where m <= 1/4 ,x=0 , y =0
0=1/4*0+b
b=0
So ,BE is y =1/4*x+0
y=x/4
now by solving
x=3.........(1)
y=x/4...........(2)
we get y= 3/4
So orthocenter coordinate are (3,3/4)
i hope its help you
please mark brainliest.
O is the orthocentre triangle
By considering the coordinates of B ,C,A we can cinclude that :
Equation of BC is y=0 .......(1)
equation of AD is x=3 ......(2)
As we know slope of BBC (begin in on the x axis)=0
and for a vertical line AD however the slope is not defined. it does not have a slope
we take the slope of AC = (4-0)/(3-4)=4/-1=-4
So the slope of its perpendicular BE has to be its negative reciprocal . that is the slope of the= 1/4
So equation of bird which is passing through (0,0) has to be y= mx + b , where m <= 1/4 ,x=0 , y =0
0=1/4*0+b
b=0
So ,BE is y =1/4*x+0
y=x/4
now by solving
x=3.........(1)
y=x/4...........(2)
we get y= 3/4
So orthocenter coordinate are (3,3/4)
i hope its help you
please mark brainliest.
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