Question

OSC
on?
5.
An object moves at 10 km/h for 10 minutes and then moves 15 km/h for 15 minutes. Find:
a) Total distance travelled by the object
b) Average speed of the ob
HOTS​

Answer 1

Explanation:

Given,

Initial velocity, u=5Km/h

Time, t=10min=

6

1

h

The bicycle is going with constant velocity, a = 0

s=ut+

2

1

at

2

s=ut

s=5×

6

1

s=

6

5

Km..........(1)

In case (2),

u=5Km/h

v=0

a=1Km/h

2

Using equation of motion as,

v

2

−u

2

=2as

0−(5)

2

=2(−1)s

s=

2

25

Km

Total distance,

=

6

5

+

2

25

=13.33Km

Total distance covered by bicycle is 13.33Km.