Question

Osmotic pressure of a solution containing 2 g dissolved
protein per 300 cm of solution is 20 mm of Hg at 27°C.
The molecular mass of protein is:
a)6239.3 g mol- b)12315.5 g mol-1
c)3692.1 g mod)7368.4l- g mol-​

Answer 1

Given :

Mass of the protein = 2g

Osmotic pressure = 20mm of Hg

                              = (20/760) atm

Volume of the solution= 300 cm³

Temperature of the solution = 27°C

To Find :

The molecular mass of the protein

Solution :

• The osmotic pressure of the solution is given by

                 $\pi =iMRT$

• By substituting the given values in the above formula, we get

                 $\pi =\frac{2\times0.0821 \times300}{Mw \times0.3}$

                $\frac{20}{760} =\frac{2\times0.0821 \times300}{Mw \times0.3}$

                $Molecular\:weight = 6239 \:g/mol$

The molecular mass of the protein is 6239 g/mol

Answer 2

Answer:

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Blazing 'cross the evening sky

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Like a rainbow

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