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Find the sum of n terms of the series whose n^th
term is not n(n+1)
Answers
Answered by
0
Answer:
Correct option is
A
3
n(n+1)(n+2)
T
n
=n(n+1)=n
2
+n
∴ Sum = S
n
=∑T
n
=∑n
2
+∑n=
6
n(n+1)(2n+1)
+
2
n(n+1)
=
6
n(n+1)
(2n+1+3)=
3
n(n+1)(n+2)
Hence, option 'A' is correct.
Answered by
0
Tn = n(n+1) = n²+n
Sn = ∑Tn
= ∑n² +∑n
= [n(n+1)(2n+1)]/6 + [n(n+1)]/2
= [n(n+1)/6] {(2n+1+3)}=
= [n(n+1)(n+2)2]/6
= [n(n+1)(n+2)]/3
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