Question

out of 10 consonant and 5 vowels.how much different words can be formed each containing 3 consonants and 2 vowels.​

Answer 1

Step-by-step explanation:

Total consonants = 10

To be taken = 3

10C3 = 10!/7!3!

= 10 × 9 × 8 /1 × 2 × 3

= 120

Total vowels = 5

To be taken = 2

5C2 = 5!/2!3!

= 5 × 4 / 2

= 10

By multiplication principle

Total no. of ways = 120 × 10

= 1200

THANKS