Out of 12 pens, 4 are defective. Three pens are drawn at random. What is the probability that: i) at least two are defective ii) atmost two are non defective?
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I am not sure but I think
i) 4/8 = 1/2
ii) 7/8
ShashwatKaushik3:
Bata de sahi hai??
Answered by
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I think this one is the correct explanation for it ... bt a little bit confusion in 2 nd part...
I hope it will help u ...
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