Out of 250 bulbs in a box, 35 bulbs are defective. One bulb is taken out at random from the box. Find the probability that the drawn bulb is not defective.
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Answered by
49
Out of 250 bulbs in a box one bulb can be chosen in 250 ways.
Total number of outcomes = 250
Number of defective bulbs= 35
Number of non defective bulbs= 250 - 35 = 215
Number of favourable outcomes = 215
Probability = Number of favourable outcomes / Total number of outcomes
P(getting a non defective bulb)= 215/250= 43/50
Hence,that the drawn bulb is not defective 43/50.
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Total number of outcomes = 250
Number of defective bulbs= 35
Number of non defective bulbs= 250 - 35 = 215
Number of favourable outcomes = 215
Probability = Number of favourable outcomes / Total number of outcomes
P(getting a non defective bulb)= 215/250= 43/50
Hence,that the drawn bulb is not defective 43/50.
HOPE THIS WILL HELP YOU...
Anonymous:
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Answered by
17
total no of bulbs = 250
total no of outcomes = 250
no of defective piece = 35
favorable no of outcomes = 35
probability of geeting defective piece = 35/250
= 7/50..
probability of geeting defective ones = 1 - probability of geeting defective ones
= 1 - 7/ 50
= 43 / 50......
[ probability = favorable no of outcomes / total no of outcomes ]
total no of outcomes = 250
no of defective piece = 35
favorable no of outcomes = 35
probability of geeting defective piece = 35/250
= 7/50..
probability of geeting defective ones = 1 - probability of geeting defective ones
= 1 - 7/ 50
= 43 / 50......
[ probability = favorable no of outcomes / total no of outcomes ]
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