Out of 30 consecutive numbers , 2 are chosen at random .find the probability that their sum is odd
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1/2 is probabbility
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Case 1,
The chosen number are odd and even
Thus their sum will be odd
P( getting odd ) = 1
Case 2
The chosen number are both odd
Thus their sum will be even
P( getting odd ) = 0
Case 3
The chosen numbers are both even
Thus their sum will be also even
P( getting odd ) = 0
Summing the three cases
P( getting odd ) = 1/3
Thus the answer is 1/3
Hope this helps
The chosen number are odd and even
Thus their sum will be odd
P( getting odd ) = 1
Case 2
The chosen number are both odd
Thus their sum will be even
P( getting odd ) = 0
Case 3
The chosen numbers are both even
Thus their sum will be also even
P( getting odd ) = 0
Summing the three cases
P( getting odd ) = 1/3
Thus the answer is 1/3
Hope this helps
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