Question

Out of 500 items selected for inspection 0.2% are found to be defective find how many lots will certain exactly no defective if there are 1000 let's use poisson distribution

Answer 1

Answer:

998

Step-by-step explanation:

out of 500, 0.2% are defective

so 500x0.2/100=1

for 500 its 1 so for 1000 it will be 2

therefore, 1000-2=998

Answer 2

Answer:

The Poisson distribution is 367.9

Step-by-step explanation:

• Poisson distribution: Poisson distribution is the probability of finding a specific value.
• The formula for Poisson distribution is: $P =\frac{e^{-m} m^x}{x!}$

         Where x = random variable and m = average rate of value.

• Calculation: The average rate of value = m = 0.2% of 500

                                                                                 = $\frac{0.2}{100} \times 500$ = 1

      If defective is zero then, x = 0.

So Poisson distribution, P = $\frac{e^{-1}1^0 }{0!}$ = $e^{-1}$ = 0.3679  [From Poisson's table]

For 1000, the Poisson distribution will be = 1000P = 1000 × 0.3679

                                                                                   = 367.9

The Poisson distribution is 367.9

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