out of 50families in a certain town 29 own a coupe and 24 own a van. If 2families don't own either of them. what fraction of the families own both a coupe and a van?
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Answer:
GIVEN :
families don't own either of them = 2
total families = 50
total families who won prises = n(A ∪ B)
= 50 - 2
= 48
families own a coupe = n(A)
= 29
families own a van = n(B)
= 24
families own both a coupe and a van
= n(A ∩ B )
n(A ∪ B) = n(A) + n(B) - n(A ∩ B )
48 = 29 + 24 - n(A ∩ B )
n(A ∩ B ) = 29 +24 - 48
n(A ∩ B ) = 53 - 48
n(A ∩ B ) = 5
.: fraction of the families own both a coupe and a van is 5 families
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