Question

Out of a certain amount of money a boy spends 3/5 and then 1/4 of the remainder. He has rupees 15 left.how much amount had he at first

Answer 1

Answer:

Amount he had at first = 50

Step-by-step explanation:

Out of a certain amount of money a boy spends 3/5 and then 1/4 of the remainder. He has rupees 15 left.

Let say boy had  Amount =  20 M

Amount Spend = (3/5) * 20M = 12M

Remainder Amount  = 20M - 12M = 8M

1/4 of remainder is spent = (1/4) * 8M = 2M

Final amount Left = 8M - 2M = 6M

6M = 15

=> M = 5/2

20M = 20(5/2)

=> 20M = 50

Amount he had at first = 50

Answer 2

Answer:

The required amount is Rs. 50

Step-by-step explanation:

Let the amount he had at first be Rs. x

Amount spent

$=\frac{3}{5}\:of\:x$

$=\frac{3x}{5}$

Amount remaining

$=x-\frac{3x}{5}$

$=\frac{2x}{5}$

Amount spent on second time

$=\frac{1}{4}\:of\:\frac{2x}{5}$

$=\frac{2x}{20}$

$=\frac{x}{10}$

Amount remaining at the end = Rs.15

That is

$\frac{2x}{5}-\frac{x}{10}=15$

$\frac{4x-x}{10}=15$

$\frac{3x}{10}=15$

$3x=150$

$x=\frac{150}{3}$

$x=50$

Therefore, amouint he had at first is Rs 50