Out of a certain sum of money a boy spends 3/5, and then 1/4 of the remainder. He has ₹ 15 left. How much amount had he first
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answer for the given problem is given
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Answer:
Rs.50/-
Step-by-step explanation:
Let money = x
He spends 3/5th of x => 3x/5
Remainder = x-3x/5
He then spends 1/4th of the remainder
=> (1/4)(x-(3x/5)) = (x/4)-(3x/20)
Remaining money = x-(3x/5)-[(x/4)-(3x/20)] = 15
(20x/20) - (12x/20) - (5x/20) + (3x/20) = 15
20x - 12x - 5x + 3x = 300
6x = 300
x = 50
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