Question

Out of a certain sum of money a boy spends 3/5, and then 1/4 of the remainder . He has ruppees 15 left . How much amount he had first?​

Answer 1

Answer:

rs. 50

Step-by-step explanation:

Hey There!

here is your solution step by step!

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Let the total money be X

So,

the boy spend = 3/5 × X = rs. 3X/5

remaining = X - 3X/5 = (5X - 3X)/5 = 2X/5

1/4 of the remaining = 2X/5 × 1/4 = X/10

Money left = 2X/5 - X/10

rs. 15 = (4X - X)/10

rs. 15 = 3X/10

rs. 15 × 10/3 = X

rs. 50 = X

X = rs. 50

So,

amount he had first = rs. 50

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Hope it's helpful for you!

Answer 2

Answer:

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