Question

Out of a group of swans ,7/2 times the squareroot of the no are playing on the shore of a tank .the two remaining ones are playing with amorpus fight in the water .what is the total no of swans?

Answer 1

Hi........ Here is the answer

Answer 2

Answer:

In the group of swans, total sixteen swans present playing on the shore as well as fighting in the water.  .

Step-by-step explanation:

Consider that x is the total number of swans.

Swans playing on the shore $=\frac{7}{2}\sqrt{x}$

The number of swans fighting in the water =2

Total no. of swans $x=\frac{7}{2} \sqrt{x}+2$                 ...............(1)

Put $x=y^{2}$ in eq.(1)

We get    $y^{2}-\frac{7}{2} y-2=0$

               $2y^{2}-7y-4=0\\2y^{2}-8y+y-4=0\\2y(y-4)+(y-4)=0\\(y-4)(2y+1)=0\\y=4$

Therefore    $x=y^{2}=(4)^{2}=16$

Hence sixteen swans are present in the group.