Out of a group of swans, times the square root of the total number are plaut.
on the shore of a tank. The two remaining ones are playing, with amorous fights
in the water. What is the total number of swans?
Answers
★ l l Correct Question l l ★
Out of a group of swans, times the square root of the total number are playing on the shore of a tank. The two remaining ones are playing, with amorous fight
in the water. What is the total number of swans?
★ l l Answer l l ★
Let the number of swan be x .
Then, the number of swans playing on the shore of the tank = 7/2 √x
Remaining swans = 2
x = 7/2 √x + 2
➠ x - 2 = 7/2 √x
Squaring both sides
➠ ( x - 2 )² = ( 7/2 )² x
➠ x² - 4x + 4 = 49x/4
➠ 4 ( x² - 4x + 4 ) = 49x
➠ 4x² - 16x + 16 = 49x
➠ 4x² - 16x + 16 - 49x = 0
➠ 4x² - 65x + 16 = 0
➠ 4x² - 64x - x + 16 = 0
➠ 4x ( x - 16 ) - 1 ( x - 16 ) = 0
➠ ( x - 16 ) ( 4x - 1 ) = 0
➠ x = 16 and x = 1/4
We reject x = ¼ as the number of swan cannot be fraction ¼ and take x = 16b.
Hence, the total number of swans is 16 .
Answer:
Let the number of swans be x.
Then , the number of swans playing on the shore of the tank = 7/2√x
Remaining swans = 2
x = 7/2√x + 2
x - 2 = 7/2√x
Squaring both sides
(x - 2)² = (7/2)²x
x² - 4x + 4 = 49x/4
4(x² - 4x + 4) =49x
4x² - 16x + 16 = 49x
4x² - 16x + 16 - 49x = 0
4x² - 65x + 16 = 0
4x² - 64x - X + 16 = 0
4x(x - 16) - 1(x - 16) = 0
(x - 16)(4x - 1) = 0
x = 16. and x = 1/4.
We reject x = 1/4 as the number of swan can't be fraction 1/4 and take x = 16b
hence, the total number of swans is 16.
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