Out of a sum of Rs 850, a part was lent at 6% SI and the other at 12% SI. If the interest on the first part after 2 years is equal to the interest on the second part after 4 years, then the second sum is?
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Equation of finding S.I is
S.I=P.N.R/100
In the given question let us assume the principal of 1st part as x ,hence the principal of 2nd part be (850-x)
S.I of 1st part = x.6.2/100------(1)
S.I of 2nd part = (850-x).12.4/100----(2)
Equating (1) & (2)
x.6.2/100=(850-x)12.4/100
12x/100=(850-x)48/100
x=(850-x)4
x=3400-4x
5x=3400
x=680
Since 1st part being 680
2nd part=(850-680)=170
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