Question

Out of AlCl3 and NaCl, which is more effective in causing coagulation of a negative sol? Give reason.

Answer 1

By hardly schulze rule, for a negatively charged sol, positively charged ion with higher oxidation state is a better coagulating agent. Since AlCl​3 forms Al3+ ion and NaCl forms Na+1 only, AlCl3 is a better coagulating agent.

Answer 2

$AlCl_3$ is more effective in causing coagulation of a negative sol.

Explanation:

• The coagulation of the negative sol depends on the charge that is present on the opposite sign charge of the salt ions.

• The given sol is negative so we will consider only the positive ions charge of the given salts.

• NaCl is of the the salt given to us. This contains of the ions $Na^+$ and $Cl^-$.

• Here the opposite charged ion to the negative sol is the cation $Na^+$. It has the magnitude is 1. So its value is +1 as it is a cation.

• The other salt given to us is $AlCl_3.$. This contains of the ions$Al_3^+$and$Cl^-.$.

• Here the $Al3^+$ is the cation which the negative sol. It has the magnitude of 3 so its value is +3.

• When both $Na^+$ and $Al3^+$ ions are compared, the$Al3^+$ has more magnitude in its ion.

• Hence$AlCl_3$ salt will have the better effect in causing coagulation of negative sol than NaCl salt.

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