Question

Out of many habits that Navdeep has resolved to change in himself, the most prominent is the habit of coming late in office. He carefully observed and found out that his probability of going by car A, B, C and D are 1/7. 3/7, 2/7 and 1/7 respectively. On further analysis, he figured out that his probability of getting late if he goes by car A, B, C and D are 8/9. 4/9. 5/9 and 4/9 respectively. On a particular day. he wants to go by car A. Can you tell us the probability of Navdeep travelling by car A, if he reaches office on time.​

Answer 1

Answer:

Step-by-step explanation:

Required probability =  

7

1

​

×  

9

7

​

+  

7

3

​

×  

9

8

​

+  

7

2

​

×  

9

5

​

+  

7

1

​

×  

9

8

​

 

7

1

​

×  

9

7

​

 

​

=  

7

1

​

Answer 2

The probability of Navdeep travelling by car A, if he reaches office on time is 1/63

Given,

Out of many habits that Navdeep has resolved to change in himself, the most prominent is the habit of coming late in office. He carefully observed and found out that his probability of going by car A, B, C and D are 1/7. 3/7, 2/7 and 1/7 respectively. On further analysis, he figured out that his probability of getting late if he goes by car A, B, C and D are 8/9. 4/9. 5/9 and 4/9 respectively.

To find,

On a particular day. he wants to go by car A. Can you tell us the probability of Navdeep travelling by car A, if he reaches office on time.​

Solution,

P(going by car A) = 1/7

P(getting late by car A) = 8/9

P(getting on time by car) = 1 - 8/9 = 1/9

Pgoing by Car A and reaching on time) = $\frac{1}{7}$ × $\frac{1}{9}$  = $\frac{1}{63}$

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