Question

out of the following equation which equation has 3 as a solution.(A) x² - 6= 0 (B) x² + x-6=0 (C) x²-x+6=0 (D) x² + x+6=0​

Answer 1

Answer:

c

Step-by-step explanation:

option c has 3 as a root

${x}^{2} - 3x + 2x - 6 = 0$

x(x-3)+2(x-3)

(x+2)(x-3)

x = -2,3

Answer 2

Answer:

C)

Step-by-step explanation:

a) Substituting x with 3, we get:

(3)² - 6 = 0

9 - 6 is not equal to 0 hence a) is not the solution.

b) Substituting x with 3:

(3)² + 3 - 6 = 0

9 + 3 - 6 = 0

12 - 6 = 0 is not correct!

c) Substituting x with 3:

(3)² - 3 + 6 = 0

9 - 3 + 6 = 0

6 - 6 = 0

Hence, option C) has the solution as 3.

Hope it helps!