Question

Output of following equation is (BCD)'+A'B(CD) +AB(CD)+(AB)'CD+AB'CD+
(AB) CD +A'BCD'+ABCD'
Options
D+BC
D'+B'C.
B+D'C
B+DC
Clear​

Answer 1

To simplify the given equation, we can use the rules of Boolean algebra.

First, we can use the identity A+A' = 1 to simplify the first and last terms:

(BCD)'+A'B(CD) = 1 +A'B(CD)

A'BCD'+ABCD' = A'(BCD)'+ABCD' = 1+ABCD'

Next, we can use the identity A+1 = 1 to simplify the third term:

AB(CD)+(AB)'CD+AB'CD+ (AB) CD = AB(CD)+(AB)'CD+AB'CD+ AB CD = AB(CD+(CD)') = AB(1) = AB

Then, we can use the identity A+A = A to simplify the second term:

A'B(CD) +AB(CD) = (A'+A)B(CD) = AB(CD)

Now, we can use the identity A+0 = A to simplify the fourth term:

A'BCD'+ABCD' = A'BCD'+ABCD'+0 = A'BCD'+ABCD'

Finally, we can use the identity A+A = A to simplify the fifth term:

AB'CD+AB CD = (AB')+(AB) CD = AB

Putting it all together, the simplified equation is:

1 +AB(CD) +AB +A'BCD'+ABCD' = D+BC

Therefore, the correct answer is D+BC.

To learn more about Boolean algebra from the given link.

https://brainly.in/question/3899228

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