Question

Over a wire of length 86 cm is bent in the form of a rectangle that its length is 77 CM more than its breadth find the length and the breadth of the rectangle so formed

Answer 1

Total length of Wire= Perimeter Of Rectangle

Let Its Breadth = 'x'

So Its Length = 'x+77'

Perimeter Of Rectangle= Total length of Wire [Perimeter = 2(l +b)]

2(x + x +77) = 86

2x + 77 = 86/2

2x + 77 = 43

2x = 43 -77 

2x = -34

x = -17cm 

 

.'.Breadth = -17cm

Length = x + 7

             = -17 + 7

             = -10cm