Question

ox Numerical questions 1. The breadth of an iron door is 2.4 m. If the minimum torque required to open the door is 50 Nm, what is the minimum force required to open the door? (Ans 20.8 N) lied on the spanner at a length of 0.25 m from the bolt is​

Answer 1

Answer:

Breadth = 2.4 m

⇒ Moment of force (Torque) = Force × r (tow)

[We will take Breadth (2.4 m) as tow.]

⇒ 50 = Force × 2.4

∴ Force = 50/2.4

Now, We will remove the decimal :-

So, Force = 500/24

= 20.8 N

Hence, Force required to open the door is 20.8 N

Explanation:

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