Oxidation method of balacing equation K2Cr2O7+H2SO4+KI----K2SO4+Cr2(SO4)3+I2+H2O
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Without spectator ions.
Oxidation Half-reaction : 2I(-) ------>I2 +2e -----(1)
Reduction Half-reaction:
Cr2O7(2-) + 14H(+) + 5e ----->2Cr(3+) +7H2O ----(2)
Now,
(1)×5+(2)×2=> 10I(-) +2Cr2O7(2-) +28H(+) =5I2 +4Cr(3+) +14H2O
With spectator ions: 10KI +2K2Cr2O7 +14H2SO4=Cr2(SO4)3+5I2+7K2SO4+14H2O
Oxidation Half-reaction : 2I(-) ------>I2 +2e -----(1)
Reduction Half-reaction:
Cr2O7(2-) + 14H(+) + 5e ----->2Cr(3+) +7H2O ----(2)
Now,
(1)×5+(2)×2=> 10I(-) +2Cr2O7(2-) +28H(+) =5I2 +4Cr(3+) +14H2O
With spectator ions: 10KI +2K2Cr2O7 +14H2SO4=Cr2(SO4)3+5I2+7K2SO4+14H2O
chandruchiefpaj400:
Cr and S not balance
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