Oxidation number of cr in k3[cr(c2o4)3]
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The oxalate ion get 2 electrons
3 oxalate ions get 2 x 3 = 6 electrons
the K atoms donate 3 electrons
So, oxidation state of chromium = +3 + x - 6= 0
I stated 0 here, since the overall charge of the complex is 0
=> x = +6 - 3 = +3
So, oxidation state of chromium is +3
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