Question

Oxidation number of Fe in K4(Fe(CN6))4-

Answer 1

Answer:

+2

Explanation:

Let the oxidation number of Fe be x.

Oxidation number of CN=−1, K=+1.

In K4 [Fe(CN)6]:

4×1+x+6×(-1) =0

4+x - 6= 0

Or

x = +2

The oxidation state of Fe in K4[ Fe( CN 6) ] is +2