Question

Oxidation number of N in NH4NO2

Answer 1

Answer : The oxidation number of N in $NH_4NO_2$ are, (-3) and (+3).

Explanation :

In the given molecule $NH_4NO_2$, has two different types of N.

The given molecule is made up of the combination of two ion which are ammonium ion $NH_4^+$ and nitrite ion $NO_2^-$. In this nitrite ion is the counter ion.

Now we have to determine the oxidation number of N in both the ions.

The oxidation number of N in $NH_4^+$ :

Let the oxidation number of 'N' be 'x'.

$x+4(+1)=+1\\\\x=-3$

The oxidation number of N in $NO_2^-$ :

Let the oxidation number of 'N' be 'x'.

$x+2(-2)=-1\\\\x=+3$

Hence, the oxidation number of N in $NH_4NO_2$ are, (-3) and (+3).